Base | Representation |
---|---|
bin | 1011111011101100001110… |
… | …1111110110000010110111 |
3 | 1201110021022022121011212012 |
4 | 2332323003233312002313 |
5 | 3204424443220034424 |
6 | 43523144113114435 |
7 | 2522616442546334 |
oct | 276730357660267 |
9 | 51407268534765 |
10 | 13120114221239 |
11 | 41a9233489a33 |
12 | 157a923858a1b |
13 | 7422b57252cc |
14 | 3350345c198b |
15 | 17b43e6a0b0e |
hex | beec3bf60b7 |
13120114221239 has 4 divisors (see below), whose sum is σ = 13315936821624. Its totient is φ = 12924291620856.
The previous prime is 13120114221229. The next prime is 13120114221259. The reversal of 13120114221239 is 93212241102131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13120114221239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120114221229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97911300092 + ... + 97911300225.
It is an arithmetic number, because the mean of its divisors is an integer number (3328984205406).
Almost surely, 213120114221239 is an apocalyptic number.
13120114221239 is a deficient number, since it is larger than the sum of its proper divisors (195822600385).
13120114221239 is an equidigital number, since it uses as much as digits as its factorization.
13120114221239 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195822600384.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 13120114221239 in words is "thirteen trillion, one hundred twenty billion, one hundred fourteen million, two hundred twenty-one thousand, two hundred thirty-nine".
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