131201202413441 has 2 divisors, whose sum is σ = 131201202413442. Its totient is φ = 131201202413440.

The previous prime is 131201202413419. The next prime is 131201202413473. The reversal of 131201202413441 is 144314202102131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85969242241600 + 45231960171841 = 9271960^2 + 6725471^2 .

It is an emirp because it is prime and its reverse (144314202102131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131201202413441 is a prime.

It is not a weakly prime, because it can be changed into another prime (131201202413041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600601206720 + 65600601206721.

It is an arithmetic number, because the mean of its divisors is an integer number (65600601206721).

Almost surely, 2^{131201202413441} is an apocalyptic number.

It is an amenable number.

131201202413441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201202413441 is an equidigital number, since it uses as much as digits as its factorization.

131201202413441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131201202413441 its reverse (144314202102131), we get a palindrome (275515404515572).

The spelling of 131201202413441 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred two million, four hundred thirteen thousand, four hundred forty-one".