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131201204033381 is a prime number
BaseRepresentation
bin11101110101001110101001…
…001010010001011101100101
3122012112201020111022122001012
4131311032221022101131211
5114144100031213032011
61143013000121112005
736430655100422066
oct3565165112213545
9565481214278035
10131201204033381
11388941332a5429
121286b809928605
1358292b3447181
14245825a58656d
151027c9ed19a8b
hex7753a9291765

131201204033381 has 2 divisors, whose sum is σ = 131201204033382. Its totient is φ = 131201204033380.

The previous prime is 131201204033359. The next prime is 131201204033443. The reversal of 131201204033381 is 183330402102131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96641502470881 + 34559701562500 = 9830641^2 + 5878750^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201204033381 - 218 = 131201203771237 is a prime.

It is a super-2 number, since 2×1312012040333812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131201204038381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600602016690 + 65600602016691.

It is an arithmetic number, because the mean of its divisors is an integer number (65600602016691).

Almost surely, 2131201204033381 is an apocalyptic number.

It is an amenable number.

131201204033381 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201204033381 is an equidigital number, since it uses as much as digits as its factorization.

131201204033381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 131201204033381 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred four million, thirty-three thousand, three hundred eighty-one".