Base | Representation |
---|---|
bin | 111101000110000110… |
… | …0111001011010010010 |
3 | 110112122122020000222011 |
4 | 1322030030321122102 |
5 | 4122200002210002 |
6 | 140134545133134 |
7 | 12323200612222 |
oct | 1721414713222 |
9 | 415578200864 |
10 | 131201210002 |
11 | 50707731a75 |
12 | 2151702a1aa |
13 | c4aba00995 |
14 | 64c8c32082 |
15 | 362d53c8d7 |
hex | 1e8c339692 |
131201210002 has 4 divisors (see below), whose sum is σ = 196801815006. Its totient is φ = 65600605000.
The previous prime is 131201209999. The next prime is 131201210003. The reversal of 131201210002 is 200012102131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 114691272921 + 16509937081 = 338661^2 + 128491^2 .
It is not an unprimeable number, because it can be changed into a prime (131201210003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32800302499 + ... + 32800302502.
Almost surely, 2131201210002 is an apocalyptic number.
131201210002 is a deficient number, since it is larger than the sum of its proper divisors (65600605004).
131201210002 is an equidigital number, since it uses as much as digits as its factorization.
131201210002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65600605003.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 131201210002 its reverse (200012102131), we get a palindrome (331213312133).
The spelling of 131201210002 in words is "one hundred thirty-one billion, two hundred one million, two hundred ten thousand, two".
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