Base | Representation |
---|---|
bin | 1011111011101100010010… |
… | …1101101001000111100110 |
3 | 1201110021100110002020001120 |
4 | 2332323010231221013212 |
5 | 3204430011341434342 |
6 | 43523145452234410 |
7 | 2522620030340526 |
oct | 276730455510746 |
9 | 51407313066046 |
10 | 13120130421222 |
11 | 41a9241644250 |
12 | 157a92916ba06 |
13 | 7422b8ba7bb6 |
14 | 3350367db686 |
15 | 17b440d00aec |
hex | beec4b691e6 |
13120130421222 has 64 divisors (see below), whose sum is σ = 28735121226240. Its totient is φ = 3960608198400.
The previous prime is 13120130421157. The next prime is 13120130421227. The reversal of 13120130421222 is 22212403102131.
It is a junction number, because it is equal to n+sod(n) for n = 13120130421192 and 13120130421201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120130421227) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 202061322 + ... + 202126242.
It is an arithmetic number, because the mean of its divisors is an integer number (448986269160).
Almost surely, 213120130421222 is an apocalyptic number.
13120130421222 is an abundant number, since it is smaller than the sum of its proper divisors (15614990805018).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120130421222 is a wasteful number, since it uses less digits than its factorization.
13120130421222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76589.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13120130421222 its reverse (22212403102131), we get a palindrome (35332533523353).
The spelling of 13120130421222 in words is "thirteen trillion, one hundred twenty billion, one hundred thirty million, four hundred twenty-one thousand, two hundred twenty-two".
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