Base | Representation |
---|---|
bin | 11101110101001110110000… |
… | …000010000111110100111111 |
3 | 122012112201112112021200020221 |
4 | 131311032300002013310333 |
5 | 114144100300222243104 |
6 | 1143013015400322211 |
7 | 36430661000454052 |
oct | 3565166002076477 |
9 | 565481475250227 |
10 | 131201319337279 |
11 | 38894192399a04 |
12 | 1286b840473367 |
13 | 58293012b8729 |
14 | 245826b9dca99 |
15 | 1027ca9ee3c54 |
hex | 7753b0087d3f |
131201319337279 has 2 divisors, whose sum is σ = 131201319337280. Its totient is φ = 131201319337278.
The previous prime is 131201319337261. The next prime is 131201319337343. The reversal of 131201319337279 is 972733913102131.
It is a weak prime.
It is an emirp because it is prime and its reverse (972733913102131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131201319337279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131201319337259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600659668639 + 65600659668640.
It is an arithmetic number, because the mean of its divisors is an integer number (65600659668640).
Almost surely, 2131201319337279 is an apocalyptic number.
131201319337279 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201319337279 is an equidigital number, since it uses as much as digits as its factorization.
131201319337279 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1285956, while the sum is 52.
The spelling of 131201319337279 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred nineteen million, three hundred thirty-seven thousand, two hundred seventy-nine".
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