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131201321132017 is a prime number
BaseRepresentation
bin11101110101001110110000…
…001000111101111111110001
3122012112201112122122212011201
4131311032300020331333301
5114144100301202211032
61143013015503011201
736430661021640403
oct3565166010757761
9565481478585151
10131201321132017
1138894193405364
121286b840b99b01
1358293017965c6
14245826bd48b73
151027caa24a8e7
hex7753b023dff1

131201321132017 has 2 divisors, whose sum is σ = 131201321132018. Its totient is φ = 131201321132016.

The previous prime is 131201321131981. The next prime is 131201321132033. The reversal of 131201321132017 is 710231123102131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131109805201761 + 91515930256 = 11450319^2 + 302516^2 .

It is an emirp because it is prime and its reverse (710231123102131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131201321132017 - 223 = 131201312743409 is a prime.

It is not a weakly prime, because it can be changed into another prime (131201321132047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600660566008 + 65600660566009.

It is an arithmetic number, because the mean of its divisors is an integer number (65600660566009).

Almost surely, 2131201321132017 is an apocalyptic number.

It is an amenable number.

131201321132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201321132017 is an equidigital number, since it uses as much as digits as its factorization.

131201321132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 131201321132017 its reverse (710231123102131), we get a palindrome (841432444234148).

The spelling of 131201321132017 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred twenty-one million, one hundred thirty-two thousand, seventeen".