13120140420241 has 4 divisors (see below), whose sum is σ = 13126096001392. Its totient is φ = 13114184839092.

The previous prime is 13120140420227. The next prime is 13120140420293. The reversal of 13120140420241 is 14202404102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13120140420241 - 2⁵ = 13120140420209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13120140420341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2977787271 + ... + 2977791676.

It is an arithmetic number, because the mean of its divisors is an integer number (3281524000348).

Almost surely, 2^{13120140420241} is an apocalyptic number.

It is an amenable number.

13120140420241 is a deficient number, since it is larger than the sum of its proper divisors (5955581151).

13120140420241 is an equidigital number, since it uses as much as digits as its factorization.

13120140420241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5955581150.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13120140420241 its reverse (14202404102131), we get a palindrome (27322544522372).

The spelling of 13120140420241 in words is "thirteen trillion, one hundred twenty billion, one hundred forty million, four hundred twenty thousand, two hundred forty-one".