Base | Representation |
---|---|
bin | 11101110101001110110101… |
… | …000110010001000111011011 |
3 | 122012112201202110011201212222 |
4 | 131311032311012101013123 |
5 | 114144100434000404404 |
6 | 1143013032033454255 |
7 | 36430663051640633 |
oct | 3565166506210733 |
9 | 565481673151788 |
10 | 131201404309979 |
11 | 38894226357183 |
12 | 1286b864a1138b |
13 | 5829315a9a333 |
14 | 2458278ddb6c3 |
15 | 1027cb26cadbe |
hex | 7753b51911db |
131201404309979 has 2 divisors, whose sum is σ = 131201404309980. Its totient is φ = 131201404309978.
The previous prime is 131201404309961. The next prime is 131201404310003. The reversal of 131201404309979 is 979903404102131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131201404309979 is a prime.
It is a super-2 number, since 2×1312014043099792 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131201404309979.
It is not a weakly prime, because it can be changed into another prime (131201404300979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600702154989 + 65600702154990.
It is an arithmetic number, because the mean of its divisors is an integer number (65600702154990).
Almost surely, 2131201404309979 is an apocalyptic number.
131201404309979 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201404309979 is an equidigital number, since it uses as much as digits as its factorization.
131201404309979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 53.
The spelling of 131201404309979 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred four million, three hundred nine thousand, nine hundred seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •