Base | Representation |
---|---|
bin | 11101110101001110110101… |
… | …000110010001000111110011 |
3 | 122012112201202110011201220212 |
4 | 131311032311012101013303 |
5 | 114144100434000410003 |
6 | 1143013032033454335 |
7 | 36430663051640666 |
oct | 3565166506210763 |
9 | 565481673151825 |
10 | 131201404310003 |
11 | 388942263571a5 |
12 | 1286b864a113ab |
13 | 5829315a9a351 |
14 | 2458278ddb6dd |
15 | 1027cb26cadd8 |
hex | 7753b51911f3 |
131201404310003 has 2 divisors, whose sum is σ = 131201404310004. Its totient is φ = 131201404310002.
The previous prime is 131201404309979. The next prime is 131201404310023. The reversal of 131201404310003 is 300013404102131.
It is a strong prime.
It is an emirp because it is prime and its reverse (300013404102131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131201404310003 - 210 = 131201404308979 is a prime.
It is not a weakly prime, because it can be changed into another prime (131201404310023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600702155001 + 65600702155002.
It is an arithmetic number, because the mean of its divisors is an integer number (65600702155002).
Almost surely, 2131201404310003 is an apocalyptic number.
131201404310003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201404310003 is an equidigital number, since it uses as much as digits as its factorization.
131201404310003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 131201404310003 its reverse (300013404102131), we get a palindrome (431214808412134).
The spelling of 131201404310003 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred four million, three hundred ten thousand, three".
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