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131201404310401 is a prime number
BaseRepresentation
bin11101110101001110110101…
…000110010001001110000001
3122012112201202110011202110121
4131311032311012101032001
5114144100434000413101
61143013032033500241
736430663051642105
oct3565166506211601
9565481673152417
10131201404310401
1138894226357527
121286b864a11681
135829315a9a599
142458278ddb905
151027cb26cb0a1
hex7753b5191381

131201404310401 has 2 divisors, whose sum is σ = 131201404310402. Its totient is φ = 131201404310400.

The previous prime is 131201404310351. The next prime is 131201404310407. The reversal of 131201404310401 is 104013404102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125729664629776 + 5471739680625 = 11212924^2 + 2339175^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201404310401 - 239 = 130651648496513 is a prime.

It is not a weakly prime, because it can be changed into another prime (131201404310407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600702155200 + 65600702155201.

It is an arithmetic number, because the mean of its divisors is an integer number (65600702155201).

Almost surely, 2131201404310401 is an apocalyptic number.

It is an amenable number.

131201404310401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201404310401 is an equidigital number, since it uses as much as digits as its factorization.

131201404310401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131201404310401 its reverse (104013404102131), we get a palindrome (235214808412532).

The spelling of 131201404310401 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred four million, three hundred ten thousand, four hundred one".