1312014043231 has 2 divisors, whose sum is σ = 1312014043232. Its totient is φ = 1312014043230.

The previous prime is 1312014043177. The next prime is 1312014043273. The reversal of 1312014043231 is 1323404102131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312014043231 is a prime.

It is a super-2 number, since 2×1312014043231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312014043196 and 1312014043205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312014043031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656007021615 + 656007021616.

It is an arithmetic number, because the mean of its divisors is an integer number (656007021616).

Almost surely, 2^{1312014043231} is an apocalyptic number.

1312014043231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312014043231 is an equidigital number, since it uses as much as digits as its factorization.

1312014043231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1312014043231 its reverse (1323404102131), we get a palindrome (2635418145362).

The spelling of 1312014043231 in words is "one trillion, three hundred twelve billion, fourteen million, forty-three thousand, two hundred thirty-one".