Base | Representation |
---|---|
bin | 11101110101001110110110… |
… | …101101101010011000011110 |
3 | 122012112201211100011210000210 |
4 | 131311032312231222120132 |
5 | 114144101012420224202 |
6 | 1143013034442433250 |
7 | 36430663531216164 |
oct | 3565166655523036 |
9 | 565481740153023 |
10 | 131201431414302 |
11 | 3889423a68a047 |
12 | 1286b871b02826 |
13 | 582931b59a2b2 |
14 | 245827c855234 |
15 | 1027cb4c81c6c |
hex | 7753b6b6a61e |
131201431414302 has 16 divisors (see below), whose sum is σ = 262410341458320. Its totient is φ = 43732564033152.
The previous prime is 131201431414289. The next prime is 131201431414307. The reversal of 131201431414302 is 203414134102131.
It is a self number, because there is not a number n which added to its sum of digits gives 131201431414302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131201431414307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 311381493 + ... + 311802560.
It is an arithmetic number, because the mean of its divisors is an integer number (16400646341145).
Almost surely, 2131201431414302 is an apocalyptic number.
131201431414302 is an abundant number, since it is smaller than the sum of its proper divisors (131208910044018).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131201431414302 is a wasteful number, since it uses less digits than its factorization.
131201431414302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 623219147.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 131201431414302 its reverse (203414134102131), we get a palindrome (334615565516433).
The spelling of 131201431414302 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred thirty-one million, four hundred fourteen thousand, three hundred two".
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