Base | Representation |
---|---|
bin | 11101110101001110110110… |
… | …101101101110011101101111 |
3 | 122012112201211100012121222002 |
4 | 131311032312231232131233 |
5 | 114144101012421243043 |
6 | 1143013034443042515 |
7 | 36430663531316012 |
oct | 3565166655563557 |
9 | 565481740177862 |
10 | 131201431431023 |
11 | 3889423a6a0668 |
12 | 1286b871b1043b |
13 | 582931b5a4aa5 |
14 | 245827c85b379 |
15 | 1027cb4c86bb8 |
hex | 7753b6b6e76f |
131201431431023 has 2 divisors, whose sum is σ = 131201431431024. Its totient is φ = 131201431431022.
The previous prime is 131201431431019. The next prime is 131201431431043. The reversal of 131201431431023 is 320134134102131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131201431431023 - 22 = 131201431431019 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131201431431043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600715715511 + 65600715715512.
It is an arithmetic number, because the mean of its divisors is an integer number (65600715715512).
Almost surely, 2131201431431023 is an apocalyptic number.
131201431431023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201431431023 is an equidigital number, since it uses as much as digits as its factorization.
131201431431023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 131201431431023 its reverse (320134134102131), we get a palindrome (451335565533154).
The spelling of 131201431431023 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred thirty-one million, four hundred thirty-one thousand, twenty-three".
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