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131201433702319 is a prime number
BaseRepresentation
bin11101110101001110110110…
…110110011000111110101111
3122012112201211111111000121011
4131311032312312120332233
5114144101014011433234
61143013035003450051
736430663556525611
oct3565166666307657
9565481744430534
10131201433702319
1138894240a02072
121286b872826927
13582931bbbb856
14245827cc8cdb1
151027cb5084b64
hex7753b6d98faf

131201433702319 has 2 divisors, whose sum is σ = 131201433702320. Its totient is φ = 131201433702318.

The previous prime is 131201433702253. The next prime is 131201433702323. The reversal of 131201433702319 is 913207334102131.

It is a strong prime.

It is an emirp because it is prime and its reverse (913207334102131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131201433702319 is a prime.

It is a super-2 number, since 2×1312014337023192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131201433705319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600716851159 + 65600716851160.

It is an arithmetic number, because the mean of its divisors is an integer number (65600716851160).

Almost surely, 2131201433702319 is an apocalyptic number.

131201433702319 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201433702319 is an equidigital number, since it uses as much as digits as its factorization.

131201433702319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 131201433702319 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred thirty-three million, seven hundred two thousand, three hundred nineteen".