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13120193 is a prime number
BaseRepresentation
bin110010000011…
…001011000001
3220200120112002
4302003023001
511324321233
61145113345
7216343202
oct62031301
926616462
1013120193
117451439
124488855
132944b38
141a575a9
1512426e8
hexc832c1

13120193 has 2 divisors, whose sum is σ = 13120194. Its totient is φ = 13120192.

The previous prime is 13120187. The next prime is 13120199. The reversal of 13120193 is 39102131.

It is a balanced prime because it is at equal distance from previous prime (13120187) and next prime (13120199).

It can be written as a sum of positive squares in only one way, i.e., 8133904 + 4986289 = 2852^2 + 2233^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13120193 is a prime.

It is a zygodrome in base 12.

It is not a weakly prime, because it can be changed into another prime (13120199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560096 + 6560097.

It is an arithmetic number, because the mean of its divisors is an integer number (6560097).

Almost surely, 213120193 is an apocalyptic number.

It is an amenable number.

13120193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120193 is an equidigital number, since it uses as much as digits as its factorization.

13120193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

The square root of 13120193 is about 3622.1806967627. The cubic root of 13120193 is about 235.8558980963.

The spelling of 13120193 in words is "thirteen million, one hundred twenty thousand, one hundred ninety-three".