Base | Representation |
---|---|
bin | 11101110101001111100100… |
… | …100011000111010111111011 |
3 | 122012112210210221011101000112 |
4 | 131311033210203013113323 |
5 | 114144104101300321103 |
6 | 1143013243032454535 |
7 | 36431021556415115 |
oct | 3565174443072773 |
9 | 565483727141015 |
10 | 131202200401403 |
11 | 388945a476847a |
12 | 1286ba4754a44b |
13 | 58294119b2151 |
14 | 2458312a2a3b5 |
15 | 1027d0c52ecd8 |
hex | 7753e48c75fb |
131202200401403 has 4 divisors (see below), whose sum is σ = 131203661231160. Its totient is φ = 131200739571648.
The previous prime is 131202200401339. The next prime is 131202200401453. The reversal of 131202200401403 is 304104002202131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131202200401403 - 26 = 131202200401339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131202200401453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 730280150 + ... + 730459787.
It is an arithmetic number, because the mean of its divisors is an integer number (32800915307790).
Almost surely, 2131202200401403 is an apocalyptic number.
131202200401403 is a deficient number, since it is larger than the sum of its proper divisors (1460829757).
131202200401403 is an equidigital number, since it uses as much as digits as its factorization.
131202200401403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1460829756.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 131202200401403 its reverse (304104002202131), we get a palindrome (435306202603534).
The spelling of 131202200401403 in words is "one hundred thirty-one trillion, two hundred two billion, two hundred million, four hundred one thousand, four hundred three".
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