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131202212000441 is a prime number
BaseRepresentation
bin11101110101001111100101…
…001111010111001010111001
3122012112210211201222122220112
4131311033211033113022321
5114144104112233003231
61143013244125234105
736431022060124421
oct3565174517271271
9565483751878815
10131202212000441
113889460026aa5a
121286ba4b402935
13582941421379a
1424583143a9481
151027d0d57192b
hex7753e53d72b9

131202212000441 has 2 divisors, whose sum is σ = 131202212000442. Its totient is φ = 131202212000440.

The previous prime is 131202212000401. The next prime is 131202212000473. The reversal of 131202212000441 is 144000212202131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89128308126841 + 42073903873600 = 9440779^2 + 6486440^2 .

It is a cyclic number.

It is not a de Polignac number, because 131202212000441 - 238 = 130927334093497 is a prime.

It is not a weakly prime, because it can be changed into another prime (131202212000401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601106000220 + 65601106000221.

It is an arithmetic number, because the mean of its divisors is an integer number (65601106000221).

Almost surely, 2131202212000441 is an apocalyptic number.

It is an amenable number.

131202212000441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131202212000441 is an equidigital number, since it uses as much as digits as its factorization.

131202212000441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 131202212000441 its reverse (144000212202131), we get a palindrome (275202424202572).

The spelling of 131202212000441 in words is "one hundred thirty-one trillion, two hundred two billion, two hundred twelve million, four hundred forty-one", and thus it is an aban number.