131202301123431 has 24 divisors (see below), whose sum is σ = 196659552485760. Its totient is φ = 87412095172152.

The previous prime is 131202301123379. The next prime is 131202301123457. The reversal of 131202301123431 is 134321103202131.

131202301123431 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 0 + 2 + 301 + 12 + 343 + 1 = 666.

It is not a de Polignac number, because 131202301123431 - 2¹⁴ = 131202301107047 is a prime.

It is a super-2 number, since 2×131202301123431² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 131202301123395 and 131202301123404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131202301127431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 172785745 + ... + 173543418.

It is an arithmetic number, because the mean of its divisors is an integer number (8194148020240).

Almost surely, 2^{131202301123431} is an apocalyptic number.

131202301123431 is a deficient number, since it is larger than the sum of its proper divisors (65457251362329).

131202301123431 is an equidigital number, since it uses as much as digits as its factorization.

131202301123431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 346330737 (or 346330725 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 131202301123431 its reverse (134321103202131), we get a palindrome (265523404325562).

The spelling of 131202301123431 in words is "one hundred thirty-one trillion, two hundred two billion, three hundred one million, one hundred twenty-three thousand, four hundred thirty-one".