Base | Representation |
---|---|
bin | 1011111011101100101010… |
… | …1110001100111011111111 |
3 | 1201110021121110202220101121 |
4 | 2332323022232030323333 |
5 | 3204430213143344411 |
6 | 43523203453051411 |
7 | 2522622363245335 |
oct | 276731256147377 |
9 | 51407543686347 |
10 | 13120231231231 |
11 | 41a9293539303 |
12 | 157a956a86b67 |
13 | 742303a432a7 |
14 | 335045d5db55 |
15 | 17b449ab5571 |
hex | beecab8ceff |
13120231231231 has 2 divisors, whose sum is σ = 13120231231232. Its totient is φ = 13120231231230.
The previous prime is 13120231231199. The next prime is 13120231231343. The reversal of 13120231231231 is 13213213202131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13120231231231 - 25 = 13120231231199 is a prime.
It is a super-2 number, since 2×131202312312312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13120231231196 and 13120231231205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120231231831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560115615615 + 6560115615616.
It is an arithmetic number, because the mean of its divisors is an integer number (6560115615616).
Almost surely, 213120231231231 is an apocalyptic number.
13120231231231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120231231231 is an equidigital number, since it uses as much as digits as its factorization.
13120231231231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13120231231231 its reverse (13213213202131), we get a palindrome (26333444433362).
The spelling of 13120231231231 in words is "thirteen trillion, one hundred twenty billion, two hundred thirty-one million, two hundred thirty-one thousand, two hundred thirty-one".
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