1312023202331 has 4 divisors (see below), whose sum is σ = 1312287249000. Its totient is φ = 1311759155664.

The previous prime is 1312023202319. The next prime is 1312023202367. The reversal of 1312023202331 is 1332023202131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312023202331 - 2¹⁴ = 1312023185947 is a prime.

It is a super-2 number, since 2×1312023202331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312023202297 and 1312023202306.

It is not an unprimeable number, because it can be changed into a prime (1312023205331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132015881 + ... + 132025818.

It is an arithmetic number, because the mean of its divisors is an integer number (328071812250).

Almost surely, 2^{1312023202331} is an apocalyptic number.

1312023202331 is a deficient number, since it is larger than the sum of its proper divisors (264046669).

1312023202331 is an equidigital number, since it uses as much as digits as its factorization.

1312023202331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264046668.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1312023202331 its reverse (1332023202131), we get a palindrome (2644046404462).

The spelling of 1312023202331 in words is "one trillion, three hundred twelve billion, twenty-three million, two hundred two thousand, three hundred thirty-one".