Base | Representation |
---|---|
bin | 1011111011101100101011… |
… | …0101000111010110001111 |
3 | 1201110021121121011222010212 |
4 | 2332323022311013112033 |
5 | 3204430214124341333 |
6 | 43523203555553035 |
7 | 2522622414533426 |
oct | 276731265072617 |
9 | 51407547158125 |
10 | 13120233043343 |
11 | 41a9294566818 |
12 | 157a9575bb77b |
13 | 74230422904a |
14 | 3350462b22bd |
15 | 17b449d22448 |
hex | beecad4758f |
13120233043343 has 2 divisors, whose sum is σ = 13120233043344. Its totient is φ = 13120233043342.
The previous prime is 13120233043319. The next prime is 13120233043363. The reversal of 13120233043343 is 34334033202131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13120233043343 is a prime.
It is a super-2 number, since 2×131202330433432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120233043363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560116521671 + 6560116521672.
It is an arithmetic number, because the mean of its divisors is an integer number (6560116521672).
Almost surely, 213120233043343 is an apocalyptic number.
13120233043343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120233043343 is an equidigital number, since it uses as much as digits as its factorization.
13120233043343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 32.
Adding to 13120233043343 its reverse (34334033202131), we get a palindrome (47454266245474).
The spelling of 13120233043343 in words is "thirteen trillion, one hundred twenty billion, two hundred thirty-three million, forty-three thousand, three hundred forty-three".
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