131202344113 has 4 divisors (see below), whose sum is σ = 131241038848. Its totient is φ = 131163649380.

The previous prime is 131202344101. The next prime is 131202344153. The reversal of 131202344113 is 311443202131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311443202131 = 4409 ⋅70638059.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131202344113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131202344153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19342281 + ... + 19349062.

It is an arithmetic number, because the mean of its divisors is an integer number (32810259712).

Almost surely, 2^131202344113 is an apocalyptic number.

It is an amenable number.

131202344113 is a deficient number, since it is larger than the sum of its proper divisors (38694735).

131202344113 is an equidigital number, since it uses as much as digits as its factorization.

131202344113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38694734.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131202344113 its reverse (311443202131), we get a palindrome (442645546244).

The spelling of 131202344113 in words is "one hundred thirty-one billion, two hundred two million, three hundred forty-four thousand, one hundred thirteen".