Base | Representation |
---|---|
bin | 11101110101001111110001… |
… | …001110101001100101010011 |
3 | 122012112211100202110121221012 |
4 | 131311033301032221211103 |
5 | 114144110020230442212 |
6 | 1143013320112321135 |
7 | 36431030051600135 |
oct | 3565176116514523 |
9 | 565484322417835 |
10 | 131202413140307 |
11 | 388946a3861353 |
12 | 1286baa68431ab |
13 | 5829446aa9862 |
14 | 2458332da7055 |
15 | 1027d21053922 |
hex | 7753f13a9953 |
131202413140307 has 2 divisors, whose sum is σ = 131202413140308. Its totient is φ = 131202413140306.
The previous prime is 131202413140273. The next prime is 131202413140333. The reversal of 131202413140307 is 703041314202131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131202413140307 - 210 = 131202413139283 is a prime.
It is not a weakly prime, because it can be changed into another prime (131202413140397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601206570153 + 65601206570154.
It is an arithmetic number, because the mean of its divisors is an integer number (65601206570154).
Almost surely, 2131202413140307 is an apocalyptic number.
131202413140307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131202413140307 is an equidigital number, since it uses as much as digits as its factorization.
131202413140307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 131202413140307 its reverse (703041314202131), we get a palindrome (834243727342438).
The spelling of 131202413140307 in words is "one hundred thirty-one trillion, two hundred two billion, four hundred thirteen million, one hundred forty thousand, three hundred seven".
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