131202413140333 has 2 divisors, whose sum is σ = 131202413140334. Its totient is φ = 131202413140332.

The previous prime is 131202413140307. The next prime is 131202413140397. The reversal of 131202413140333 is 333041314202131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124867260057604 + 6335153082729 = 11174402^2 + 2516973^2 .

It is an emirp because it is prime and its reverse (333041314202131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131202413140333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131202413140295 and 131202413140304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131202413141333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601206570166 + 65601206570167.

It is an arithmetic number, because the mean of its divisors is an integer number (65601206570167).

Almost surely, 2^{131202413140333} is an apocalyptic number.

It is an amenable number.

131202413140333 is a deficient number, since it is larger than the sum of its proper divisors (1).

131202413140333 is an equidigital number, since it uses as much as digits as its factorization.

131202413140333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 131202413140333 its reverse (333041314202131), we get a palindrome (464243727342464).

The spelling of 131202413140333 in words is "one hundred thirty-one trillion, two hundred two billion, four hundred thirteen million, one hundred forty thousand, three hundred thirty-three".