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131202423201389 is a prime number
BaseRepresentation
bin11101110101001111110001…
…110101000001111001101101
3122012112211101110101210010212
4131311033301311001321231
5114144110030314421024
61143013321112112205
736431030233242551
oct3565176165017155
9565484343353125
10131202423201389
11388946a95033a1
121286baaa095665
135829448bc0167
142458334465861
151027d21d8ea0e
hex7753f1d41e6d

131202423201389 has 2 divisors, whose sum is σ = 131202423201390. Its totient is φ = 131202423201388.

The previous prime is 131202423201361. The next prime is 131202423201463. The reversal of 131202423201389 is 983102324202131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106409890977289 + 24792532224100 = 10315517^2 + 4979210^2 .

It is a cyclic number.

It is not a de Polignac number, because 131202423201389 - 228 = 131202154765933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131202423201359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601211600694 + 65601211600695.

It is an arithmetic number, because the mean of its divisors is an integer number (65601211600695).

Almost surely, 2131202423201389 is an apocalyptic number.

It is an amenable number.

131202423201389 is a deficient number, since it is larger than the sum of its proper divisors (1).

131202423201389 is an equidigital number, since it uses as much as digits as its factorization.

131202423201389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 131202423201389 in words is "one hundred thirty-one trillion, two hundred two billion, four hundred twenty-three million, two hundred one thousand, three hundred eighty-nine".