Base | Representation |
---|---|
bin | 11101110101001111110001… |
… | …110101000001111001101101 |
3 | 122012112211101110101210010212 |
4 | 131311033301311001321231 |
5 | 114144110030314421024 |
6 | 1143013321112112205 |
7 | 36431030233242551 |
oct | 3565176165017155 |
9 | 565484343353125 |
10 | 131202423201389 |
11 | 388946a95033a1 |
12 | 1286baaa095665 |
13 | 5829448bc0167 |
14 | 2458334465861 |
15 | 1027d21d8ea0e |
hex | 7753f1d41e6d |
131202423201389 has 2 divisors, whose sum is σ = 131202423201390. Its totient is φ = 131202423201388.
The previous prime is 131202423201361. The next prime is 131202423201463. The reversal of 131202423201389 is 983102324202131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106409890977289 + 24792532224100 = 10315517^2 + 4979210^2 .
It is a cyclic number.
It is not a de Polignac number, because 131202423201389 - 228 = 131202154765933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131202423201359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601211600694 + 65601211600695.
It is an arithmetic number, because the mean of its divisors is an integer number (65601211600695).
Almost surely, 2131202423201389 is an apocalyptic number.
It is an amenable number.
131202423201389 is a deficient number, since it is larger than the sum of its proper divisors (1).
131202423201389 is an equidigital number, since it uses as much as digits as its factorization.
131202423201389 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 131202423201389 in words is "one hundred thirty-one trillion, two hundred two billion, four hundred twenty-three million, two hundred one thousand, three hundred eighty-nine".
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