Base | Representation |
---|---|
bin | 11101110101001111110010… |
… | …001111011101011101010011 |
3 | 122012112211101221102210102012 |
4 | 131311033302033131131103 |
5 | 114144110034103130003 |
6 | 1143013321520413135 |
7 | 36431030346160601 |
oct | 3565176217353523 |
9 | 565484357383365 |
10 | 131202430130003 |
11 | 38894702405a21 |
12 | 1286bab04771ab |
13 | 582944a477a2b |
14 | 245833534a871 |
15 | 1027d227ac8d8 |
hex | 7753f23dd753 |
131202430130003 has 4 divisors (see below), whose sum is σ = 132783182300328. Its totient is φ = 129621677959680.
The previous prime is 131202430129961. The next prime is 131202430130027. The reversal of 131202430130003 is 300031034202131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131202430130003 - 238 = 130927552223059 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131202430190003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 790376085038 + ... + 790376085203.
It is an arithmetic number, because the mean of its divisors is an integer number (33195795575082).
Almost surely, 2131202430130003 is an apocalyptic number.
131202430130003 is a deficient number, since it is larger than the sum of its proper divisors (1580752170325).
131202430130003 is an equidigital number, since it uses as much as digits as its factorization.
131202430130003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1580752170324.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131202430130003 its reverse (300031034202131), we get a palindrome (431233464332134).
The spelling of 131202430130003 in words is "one hundred thirty-one trillion, two hundred two billion, four hundred thirty million, one hundred thirty thousand, three".
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