Base | Representation |
---|---|
bin | 1011111011101100101110… |
… | …0000001011011110000110 |
3 | 1201110021122101102111211220 |
4 | 2332323023200023132012 |
5 | 3204430230022114142 |
6 | 43523205041541210 |
7 | 2522622612512253 |
oct | 276731340133606 |
9 | 51407571374756 |
10 | 13120244332422 |
11 | 41a929a977437 |
12 | 157a95b344806 |
13 | 74230667c586 |
14 | 3350479b042a |
15 | 17b44ad022ec |
hex | beecb80b786 |
13120244332422 has 16 divisors (see below), whose sum is σ = 26432025080112. Its totient is φ = 4341492041600.
The previous prime is 13120244332381. The next prime is 13120244332423. The reversal of 13120244332422 is 22423344202131.
It is a happy number.
It is a super-2 number, since 2×131202443324222 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120244332423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7980683079 + ... + 7980684722.
It is an arithmetic number, because the mean of its divisors is an integer number (1652001567507).
Almost surely, 213120244332422 is an apocalyptic number.
13120244332422 is an abundant number, since it is smaller than the sum of its proper divisors (13311780747690).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120244332422 is a wasteful number, since it uses less digits than its factorization.
13120244332422 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15961367943.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 13120244332422 its reverse (22423344202131), we get a palindrome (35543588534553).
The spelling of 13120244332422 in words is "thirteen trillion, one hundred twenty billion, two hundred forty-four million, three hundred thirty-two thousand, four hundred twenty-two".
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