131203004003431 has 4 divisors (see below), whose sum is σ = 131215031056600. Its totient is φ = 131190976950264.

The previous prime is 131203004003329. The next prime is 131203004003483. The reversal of 131203004003431 is 134300400302131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131203004003431 - 2¹⁵ = 131203003970663 is a prime.

It is a super-2 number, since 2×131203004003431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131203004003396 and 131203004003405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131203004003131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6013510221 + ... + 6013532038.

It is an arithmetic number, because the mean of its divisors is an integer number (32803757764150).

Almost surely, 2^{131203004003431} is an apocalyptic number.

131203004003431 is a deficient number, since it is larger than the sum of its proper divisors (12027053169).

131203004003431 is a wasteful number, since it uses less digits than its factorization.

131203004003431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12027053168.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 131203004003431 its reverse (134300400302131), we get a palindrome (265503404305562).

The spelling of 131203004003431 in words is "one hundred thirty-one trillion, two hundred three billion, four million, three thousand, four hundred thirty-one".