Base | Representation |
---|---|
bin | 10011000101111011000… |
… | …101101110000010000001 |
3 | 11122102120122010222100102 |
4 | 103011323011232002001 |
5 | 132444014202401423 |
6 | 2442423250532145 |
7 | 163535221012604 |
oct | 23057305560201 |
9 | 4572518128312 |
10 | 1312030122113 |
11 | 466479887a77 |
12 | 192344297055 |
13 | 969545776a9 |
14 | 477071a833b |
15 | 241e0145c28 |
hex | 1317b16e081 |
1312030122113 has 2 divisors, whose sum is σ = 1312030122114. Its totient is φ = 1312030122112.
The previous prime is 1312030122097. The next prime is 1312030122121. The reversal of 1312030122113 is 3112210302131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 849156721009 + 462873401104 = 921497^2 + 680348^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312030122113 - 24 = 1312030122097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1312030122173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656015061056 + 656015061057.
It is an arithmetic number, because the mean of its divisors is an integer number (656015061057).
Almost surely, 21312030122113 is an apocalyptic number.
It is an amenable number.
1312030122113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312030122113 is an equidigital number, since it uses as much as digits as its factorization.
1312030122113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1312030122113 its reverse (3112210302131), we get a palindrome (4424240424244).
The spelling of 1312030122113 in words is "one trillion, three hundred twelve billion, thirty million, one hundred twenty-two thousand, one hundred thirteen".
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