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131203031341331 is a prime number
BaseRepresentation
bin11101110101010000010110…
…000100111001100100010011
3122012112212221211201111022102
4131311100112010321210103
5114144112302010410311
61143013501314431015
736431051266323365
oct3565202604714423
9565485854644272
10131203031341331
1138894990810994
121287003989246b
135829514ba8a91
14245839112ad35
151027d5a46943b
hex775416139913

131203031341331 has 2 divisors, whose sum is σ = 131203031341332. Its totient is φ = 131203031341330.

The previous prime is 131203031341297. The next prime is 131203031341337. The reversal of 131203031341331 is 133143130302131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131203031341331 - 218 = 131203031079187 is a prime.

It is a super-2 number, since 2×1312030313413312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131203031341294 and 131203031341303.

It is not a weakly prime, because it can be changed into another prime (131203031341337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601515670665 + 65601515670666.

It is an arithmetic number, because the mean of its divisors is an integer number (65601515670666).

Almost surely, 2131203031341331 is an apocalyptic number.

131203031341331 is a deficient number, since it is larger than the sum of its proper divisors (1).

131203031341331 is an equidigital number, since it uses as much as digits as its factorization.

131203031341331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 131203031341331 its reverse (133143130302131), we get a palindrome (264346161643462).

The spelling of 131203031341331 in words is "one hundred thirty-one trillion, two hundred three billion, thirty-one million, three hundred forty-one thousand, three hundred thirty-one".