Base | Representation |
---|---|
bin | 11101110101010000011010… |
… | …110001011010101100101001 |
3 | 122012112220011022221212122112 |
4 | 131311100122301122230221 |
5 | 114144112432142321413 |
6 | 1143013513211132105 |
7 | 36431053244042444 |
oct | 3565203261325451 |
9 | 565486138855575 |
10 | 131203110120233 |
11 | 38894a21228718 |
12 | 12870060144035 |
13 | 58295282cc408 |
14 | 245839b79665b |
15 | 1027d6232b2a8 |
hex | 77541ac5ab29 |
131203110120233 has 4 divisors (see below), whose sum is σ = 131207333925888. Its totient is φ = 131198886314580.
The previous prime is 131203110120193. The next prime is 131203110120293. The reversal of 131203110120233 is 332021011302131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131203110120233 - 210 = 131203110119209 is a prime.
It is a super-2 number, since 2×1312031101202332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 131203110120199 and 131203110120208.
It is not an unprimeable number, because it can be changed into a prime (131203110120293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2111856233 + ... + 2111918358.
It is an arithmetic number, because the mean of its divisors is an integer number (32801833481472).
Almost surely, 2131203110120233 is an apocalyptic number.
It is an amenable number.
131203110120233 is a deficient number, since it is larger than the sum of its proper divisors (4223805655).
131203110120233 is an equidigital number, since it uses as much as digits as its factorization.
131203110120233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4223805654.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 131203110120233 its reverse (332021011302131), we get a palindrome (463224121422364).
The spelling of 131203110120233 in words is "one hundred thirty-one trillion, two hundred three billion, one hundred ten million, one hundred twenty thousand, two hundred thirty-three".
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