Base | Representation |
---|---|
bin | 1011111011101101000001… |
… | …0101001011000000111010 |
3 | 1201110021212000211202211011 |
4 | 2332323100111023000322 |
5 | 3204430411241124200 |
6 | 43523221054024134 |
7 | 2522624615143555 |
oct | 276732025130072 |
9 | 51407760752734 |
10 | 13120325333050 |
11 | 41a9331671401 |
12 | 157a9824a804a |
13 | 74231a3a0240 |
14 | 33505465769c |
15 | 17b452ea25ba |
hex | beed054b03a |
13120325333050 has 192 divisors, whose sum is σ = 27482944978944. Its totient is φ = 4629112185600.
The previous prime is 13120325333041. The next prime is 13120325333083. The reversal of 13120325333050 is 5033352302131.
13120325333050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 223382787 + ... + 223441513.
It is an arithmetic number, because the mean of its divisors is an integer number (143140338432).
Almost surely, 213120325333050 is an apocalyptic number.
13120325333050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13120325333050 is an abundant number, since it is smaller than the sum of its proper divisors (14362619645894).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120325333050 is a wasteful number, since it uses less digits than its factorization.
13120325333050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58973 (or 58968 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 13120325333050 its reverse (5033352302131), we get a palindrome (18153677635181).
The spelling of 13120325333050 in words is "thirteen trillion, one hundred twenty billion, three hundred twenty-five million, three hundred thirty-three thousand, fifty".
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