1312034313441 has 4 divisors (see below), whose sum is σ = 1749379084592. Its totient is φ = 874689542292.

The previous prime is 1312034313439. The next prime is 1312034313449. The reversal of 1312034313441 is 1443134302131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1312034313441 - 2¹ = 1312034313439 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312034313399 and 1312034313408.

It is not an unprimeable number, because it can be changed into a prime (1312034313449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218672385571 + ... + 218672385576.

It is an arithmetic number, because the mean of its divisors is an integer number (437344771148).

Almost surely, 2^{1312034313441} is an apocalyptic number.

It is an amenable number.

1312034313441 is a deficient number, since it is larger than the sum of its proper divisors (437344771151).

1312034313441 is an equidigital number, since it uses as much as digits as its factorization.

1312034313441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437344771150.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 1312034313441 its reverse (1443134302131), we get a palindrome (2755168615572).

The spelling of 1312034313441 in words is "one trillion, three hundred twelve billion, thirty-four million, three hundred thirteen thousand, four hundred forty-one".