Search a number
-
+
13120404277143 = 3101179241908739
BaseRepresentation
bin1011111011101101010100…
…0010010100011110010111
31201110022001112101112202110
42332323111002110132113
53204431041443332033
643523232554042103
72522626564151352
oct276732502243627
951408045345673
1013120404277143
1141a9372191259
12157a9a4a19333
13742330850b17
14335060d27299
1517b459d98363
hexbeed5094797

13120404277143 has 16 divisors (see below), whose sum is σ = 17765777865600. Its totient is φ = 8611951072800.

The previous prime is 13120404277139. The next prime is 13120404277159. The reversal of 13120404277143 is 34177240402131.

It is not a de Polignac number, because 13120404277143 - 22 = 13120404277139 is a prime.

It is a super-3 number, since 3×131204042771433 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13120404207143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 120900133 + ... + 121008606.

It is an arithmetic number, because the mean of its divisors is an integer number (1110361116600).

Almost surely, 213120404277143 is an apocalyptic number.

13120404277143 is a deficient number, since it is larger than the sum of its proper divisors (4645373588457).

13120404277143 is a wasteful number, since it uses less digits than its factorization.

13120404277143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 241909022.

The product of its (nonzero) digits is 112896, while the sum is 39.

Adding to 13120404277143 its reverse (34177240402131), we get a palindrome (47297644679274).

The spelling of 13120404277143 in words is "thirteen trillion, one hundred twenty billion, four hundred four million, two hundred seventy-seven thousand, one hundred forty-three".

Divisors: 1 3 101 179 303 537 18079 54237 241908739 725726217 24432782639 43301664281 73298347917 129904992843 4373468092381 13120404277143