Base | Representation |
---|---|
bin | 111101000110001011… |
… | …1101110110110010011 |
3 | 110112122211120100011020 |
4 | 1322030113232312103 |
5 | 4122201214102243 |
6 | 140135130050523 |
7 | 12323234012103 |
oct | 1721427566623 |
9 | 415584510136 |
10 | 131204050323 |
11 | 507092a1a45 |
12 | 21517b79a43 |
13 | c4ac486748 |
14 | 64c9371203 |
15 | 362d8ee283 |
hex | 1e8c5eed93 |
131204050323 has 4 divisors (see below), whose sum is σ = 174938733768. Its totient is φ = 87469366880.
The previous prime is 131204050273. The next prime is 131204050339. The reversal of 131204050323 is 323050402131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131204050323 - 213 = 131204042131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131204050293 and 131204050302.
It is not an unprimeable number, because it can be changed into a prime (131204050343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21867341718 + ... + 21867341723.
It is an arithmetic number, because the mean of its divisors is an integer number (43734683442).
Almost surely, 2131204050323 is an apocalyptic number.
131204050323 is a deficient number, since it is larger than the sum of its proper divisors (43734683445).
131204050323 is an equidigital number, since it uses as much as digits as its factorization.
131204050323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43734683444.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 131204050323 its reverse (323050402131), we get a palindrome (454254452454).
The spelling of 131204050323 in words is "one hundred thirty-one billion, two hundred four million, fifty thousand, three hundred twenty-three".
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