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13120440131023 = 41320010734903
BaseRepresentation
bin1011111011101101011100…
…1011000101110111001111
31201110022011000212010000221
42332323113023011313033
53204431130133143043
643523240314332211
72522630511000541
oct276732713056717
951408130763027
1013120440131023
1141a939044a865
12157a9b4a2a067
137423380c5434
143350659bb691
1517b45d0cb8ed
hexbeed72c5dcf

13120440131023 has 4 divisors (see below), whose sum is σ = 13440450865968. Its totient is φ = 12800429396080.

The previous prime is 13120440131021. The next prime is 13120440131047. The reversal of 13120440131023 is 32013104402131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13120440131023 - 21 = 13120440131021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13120440131021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160005367411 + ... + 160005367492.

It is an arithmetic number, because the mean of its divisors is an integer number (3360112716492).

Almost surely, 213120440131023 is an apocalyptic number.

13120440131023 is a deficient number, since it is larger than the sum of its proper divisors (320010734945).

13120440131023 is an equidigital number, since it uses as much as digits as its factorization.

13120440131023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320010734944.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13120440131023 its reverse (32013104402131), we get a palindrome (45133544533154).

The spelling of 13120440131023 in words is "thirteen trillion, one hundred twenty billion, four hundred forty million, one hundred thirty-one thousand, twenty-three".

Divisors: 1 41 320010734903 13120440131023