131210011310233 has 4 divisors (see below), whose sum is σ = 131479436385280. Its totient is φ = 130940586235188.

The previous prime is 131210011310201. The next prime is 131210011310251. The reversal of 131210011310233 is 332013110012131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131210011310233 - 2⁵ = 131210011310201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131210011310533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134712536793 + ... + 134712537766.

It is an arithmetic number, because the mean of its divisors is an integer number (32869859096320).

Almost surely, 2^{131210011310233} is an apocalyptic number.

It is an amenable number.

131210011310233 is a deficient number, since it is larger than the sum of its proper divisors (269425075047).

131210011310233 is an equidigital number, since it uses as much as digits as its factorization.

131210011310233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 269425075046.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 131210011310233 its reverse (332013110012131), we get a palindrome (463223121322364).

The spelling of 131210011310233 in words is "one hundred thirty-one trillion, two hundred ten billion, eleven million, three hundred ten thousand, two hundred thirty-three".