1312100113122 has 64 divisors (see below), whose sum is σ = 2928638160000. Its totient is φ = 435441559104.

The previous prime is 1312100113099. The next prime is 1312100113157. The reversal of 1312100113122 is 2213110012131.

1312100113122 is a `hidden beast` number, since 131 + 210 + 0 + 11 + 312 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1312100113095 and 1312100113104.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12253129 + ... + 12359747.

It is an arithmetic number, because the mean of its divisors is an integer number (45759971250).

Almost surely, 2^{1312100113122} is an apocalyptic number.

1312100113122 is an abundant number, since it is smaller than the sum of its proper divisors (1616538046878).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312100113122 is a wasteful number, since it uses less digits than its factorization.

1312100113122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107632 (or 107626 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1312100113122 its reverse (2213110012131), we get a palindrome (3525210125253).

The spelling of 1312100113122 in words is "one trillion, three hundred twelve billion, one hundred million, one hundred thirteen thousand, one hundred twenty-two".