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13121003000000 = 265678921061
BaseRepresentation
bin1011111011101111100010…
…1110010001000011000000
31201110100121020222211010002
42332323320232101003000
53204433303232000000
643523412222455132
72522650454211140
oct276737056210300
951410536884102
1013121003000000
1141a964a147635
12157ab314344a8
137423c78c02bc
143350ba65a920
1517b4927128d5
hexbeef8b910c0

13121003000000 has 392 divisors, whose sum is σ = 37614934147680. Its totient is φ = 4447872000000.

The previous prime is 13121002999987. The next prime is 13121003000033. The reversal of 13121003000000 is 30012131.

13121003000000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 622989470 + ... + 623010530.

Almost surely, 213121003000000 is an apocalyptic number.

13121003000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121003000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18807467073840).

13121003000000 is an abundant number, since it is smaller than the sum of its proper divisors (24493931147680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121003000000 is an frugal number, since it uses more digits than its factorization.

13121003000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21199 (or 21164 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13121003000000 its reverse (30012131), we get a palindrome (13121033012131).

The spelling of 13121003000000 in words is "thirteen trillion, one hundred twenty-one billion, three million", and thus it is an aban number.