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131210030323 = 173837548181
BaseRepresentation
bin111101000110010111…
…0100010110011110011
3110112200020211011011201
41322030232202303303
54122204231432243
6140135502152031
712323335566361
oct1721456426363
9415606734151
10131210030323
1150711706899
1221519b82617
13c4b079b5c8
1464ca08a631
15362e1d104d
hex1e8cba2cf3

131210030323 has 4 divisors (see below), whose sum is σ = 131217595888. Its totient is φ = 131202464760.

The previous prime is 131210030299. The next prime is 131210030339. The reversal of 131210030323 is 323030012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131210030323 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131210030323.

It is not an unprimeable number, because it can be changed into a prime (131210030353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3756708 + ... + 3791473.

It is an arithmetic number, because the mean of its divisors is an integer number (32804398972).

Almost surely, 2131210030323 is an apocalyptic number.

131210030323 is a deficient number, since it is larger than the sum of its proper divisors (7565565).

131210030323 is an equidigital number, since it uses as much as digits as its factorization.

131210030323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7565564.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 131210030323 its reverse (323030012131), we get a palindrome (454240042454).

The spelling of 131210030323 in words is "one hundred thirty-one billion, two hundred ten million, thirty thousand, three hundred twenty-three".

Divisors: 1 17383 7548181 131210030323