Base | Representation |
---|---|
bin | 111101000110010111… |
… | …0110110100101011011 |
3 | 110112200020222021021201 |
4 | 1322030232312211123 |
5 | 4122204242030243 |
6 | 140135504015031 |
7 | 12323336354464 |
oct | 1721456664533 |
9 | 415606867251 |
10 | 131210111323 |
11 | 50711761735 |
12 | 2151a001477 |
13 | c4b07c9435 |
14 | 64ca0abd6b |
15 | 362e1ea04d |
hex | 1e8cbb695b |
131210111323 has 2 divisors, whose sum is σ = 131210111324. Its totient is φ = 131210111322.
The previous prime is 131210111321. The next prime is 131210111369. The reversal of 131210111323 is 323111012131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131210111323 - 21 = 131210111321 is a prime.
Together with 131210111321, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 131210111323.
It is not a weakly prime, because it can be changed into another prime (131210111321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605055661 + 65605055662.
It is an arithmetic number, because the mean of its divisors is an integer number (65605055662).
Almost surely, 2131210111323 is an apocalyptic number.
131210111323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131210111323 is an equidigital number, since it uses as much as digits as its factorization.
131210111323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 131210111323 its reverse (323111012131), we get a palindrome (454321123454).
The spelling of 131210111323 in words is "one hundred thirty-one billion, two hundred ten million, one hundred eleven thousand, three hundred twenty-three".
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