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1312103094817 is a prime number
BaseRepresentation
bin10011000101111111011…
…100000101101000100001
311122102202201110101002011
4103011333130011220201
5132444141343013232
62442434414552521
7163540065200164
oct23057734055041
94572681411064
101312103094817
11466506a99499
12192364808741
13969667172c8
1447712b61adb
15241e675c547
hex1317f705a21

1312103094817 has 2 divisors, whose sum is σ = 1312103094818. Its totient is φ = 1312103094816.

The previous prime is 1312103094733. The next prime is 1312103094833. The reversal of 1312103094817 is 7184903012131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 659369984256 + 652733110561 = 812016^2 + 807919^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312103094817 - 219 = 1312102570529 is a prime.

It is a super-2 number, since 2×13121030948172 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1312103094817.

It is not a weakly prime, because it can be changed into another prime (1312103094877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656051547408 + 656051547409.

It is an arithmetic number, because the mean of its divisors is an integer number (656051547409).

Almost surely, 21312103094817 is an apocalyptic number.

It is an amenable number.

1312103094817 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312103094817 is an equidigital number, since it uses as much as digits as its factorization.

1312103094817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 40.

The spelling of 1312103094817 in words is "one trillion, three hundred twelve billion, one hundred three million, ninety-four thousand, eight hundred seventeen".