1312103100301 has 4 divisors (see below), whose sum is σ = 1499546400352. Its totient is φ = 1124659800252.

The previous prime is 1312103100283. The next prime is 1312103100307. The reversal of 1312103100301 is 1030013012131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312103100301 - 2³⁷ = 1174664146829 is a prime.

It is a super-2 number, since 2×1312103100301² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312103100307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93721650015 + ... + 93721650028.

It is an arithmetic number, because the mean of its divisors is an integer number (374886600088).

Almost surely, 2^{1312103100301} is an apocalyptic number.

It is an amenable number.

1312103100301 is a deficient number, since it is larger than the sum of its proper divisors (187443300051).

1312103100301 is an equidigital number, since it uses as much as digits as its factorization.

1312103100301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187443300050.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1312103100301 its reverse (1030013012131), we get a palindrome (2342116112432).

The spelling of 1312103100301 in words is "one trillion, three hundred twelve billion, one hundred three million, one hundred thousand, three hundred one".