Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …100111000100001111101 |
3 | 11122102202201211222001111 |
4 | 103011333130320201331 |
5 | 132444141421201133 |
6 | 2442434423242021 |
7 | 163540100026036 |
oct | 23057734704175 |
9 | 4572681758044 |
10 | 1312103303293 |
11 | 466507121092 |
12 | 1923648a9311 |
13 | 9696678b173 |
14 | 47712bb7a8d |
15 | 241e679e1cd |
hex | 1317f73887d |
1312103303293 has 2 divisors, whose sum is σ = 1312103303294. Its totient is φ = 1312103303292.
The previous prime is 1312103303209. The next prime is 1312103303311. The reversal of 1312103303293 is 3923033012131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 894815726809 + 417287576484 = 945947^2 + 645978^2 .
It is an emirp because it is prime and its reverse (3923033012131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312103303293 - 213 = 1312103295101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312103303593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656051651646 + 656051651647.
It is an arithmetic number, because the mean of its divisors is an integer number (656051651647).
Almost surely, 21312103303293 is an apocalyptic number.
It is an amenable number.
1312103303293 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312103303293 is an equidigital number, since it uses as much as digits as its factorization.
1312103303293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 31.
The spelling of 1312103303293 in words is "one trillion, three hundred twelve billion, one hundred three million, three hundred three thousand, two hundred ninety-three".
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