131211010441 has 4 divisors (see below), whose sum is σ = 149955440512. Its totient is φ = 112466580372.

The previous prime is 131211010423. The next prime is 131211010451. The reversal of 131211010441 is 144010112131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144010112131 = 53 ⋅2717171927.

It is a cyclic number.

It is not a de Polignac number, because 131211010441 - 2¹³ = 131211002249 is a prime.

It is a super-2 number, since 2×131211010441² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131211010451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9372215025 + ... + 9372215038.

It is an arithmetic number, because the mean of its divisors is an integer number (37488860128).

Almost surely, 2^131211010441 is an apocalyptic number.

It is an amenable number.

131211010441 is a deficient number, since it is larger than the sum of its proper divisors (18744430071).

131211010441 is an equidigital number, since it uses as much as digits as its factorization.

131211010441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18744430070.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 131211010441 its reverse (144010112131), we get a palindrome (275221122572).

The spelling of 131211010441 in words is "one hundred thirty-one billion, two hundred eleven million, ten thousand, four hundred forty-one".