144010112131 has 4 divisors (see below), whose sum is σ = 146727284112. Its totient is φ = 141292940152.

The previous prime is 144010112117. The next prime is 144010112291. The reversal of 144010112131 is 131211010441.

144010112131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131211010441 = 7 ⋅18744430063.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-144010112131 is a prime.

It is a super-2 number, since 2×144010112131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144010112099 and 144010112108.

It is not an unprimeable number, because it can be changed into a prime (144010112431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1358585911 + ... + 1358586016.

It is an arithmetic number, because the mean of its divisors is an integer number (36681821028).

Almost surely, 2^144010112131 is an apocalyptic number.

144010112131 is a deficient number, since it is larger than the sum of its proper divisors (2717171981).

144010112131 is an equidigital number, since it uses as much as digits as its factorization.

144010112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2717171980.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 144010112131 its reverse (131211010441), we get a palindrome (275221122572).

The spelling of 144010112131 in words is "one hundred forty-four billion, ten million, one hundred twelve thousand, one hundred thirty-one".