Base | Representation |
---|---|
bin | 1011111011101111111100… |
… | …1011011100011100000011 |
3 | 1201110100212210210122102111 |
4 | 2332323333023130130003 |
5 | 3204434013443442011 |
6 | 43523431052200151 |
7 | 2522653240643014 |
oct | 276737713343403 |
9 | 51410783718374 |
10 | 13121111312131 |
11 | 41a96a52a6099 |
12 | 157ab61769057 |
13 | 742414184314 |
14 | 3350cabb300b |
15 | 17b49beaa121 |
hex | beeff2dc703 |
13121111312131 has 2 divisors, whose sum is σ = 13121111312132. Its totient is φ = 13121111312130.
The previous prime is 13121111312087. The next prime is 13121111312171. The reversal of 13121111312131 is 13121311112131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13121111312131 - 243 = 4325018289923 is a prime.
It is a super-2 number, since 2×131211113121312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13121111312171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560555656065 + 6560555656066.
It is an arithmetic number, because the mean of its divisors is an integer number (6560555656066).
Almost surely, 213121111312131 is an apocalyptic number.
13121111312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121111312131 is an equidigital number, since it uses as much as digits as its factorization.
13121111312131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108, while the sum is 22.
Adding to 13121111312131 its reverse (13121311112131), we get a palindrome (26242422424262).
The spelling of 13121111312131 in words is "thirteen trillion, one hundred twenty-one billion, one hundred eleven million, three hundred twelve thousand, one hundred thirty-one".
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