1312112101019 has 4 divisors (see below), whose sum is σ = 1312125054240. Its totient is φ = 1312099147800.

The previous prime is 1312112100997. The next prime is 1312112101031. The reversal of 1312112101019 is 9101012112131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312112101019 - 2⁴⁰ = 212600473243 is a prime.

It is a super-2 number, since 2×1312112101019² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312112100985 and 1312112101003.

It is not an unprimeable number, because it can be changed into a prime (1312112101099) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6323459 + ... + 6527660.

It is an arithmetic number, because the mean of its divisors is an integer number (328031263560).

Almost surely, 2^{1312112101019} is an apocalyptic number.

1312112101019 is a deficient number, since it is larger than the sum of its proper divisors (12953221).

1312112101019 is a wasteful number, since it uses less digits than its factorization.

1312112101019 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12953220.

The product of its (nonzero) digits is 108, while the sum is 23.

The spelling of 1312112101019 in words is "one trillion, three hundred twelve billion, one hundred twelve million, one hundred one thousand, nineteen".