Base | Representation |
---|---|
bin | 11101110101010111111101… |
… | …101000100101111100000111 |
3 | 122012120200001220120111002111 |
4 | 131311113331220211330013 |
5 | 114144231030031433221 |
6 | 1143021333121321451 |
7 | 36431461063102522 |
oct | 3565277550457407 |
9 | 565520056514074 |
10 | 131211211202311 |
11 | 388983a9066579 |
12 | 12871741196287 |
13 | 582a2197746c6 |
14 | 2458929653bb9 |
15 | 1028188641be1 |
hex | 7755fda25f07 |
131211211202311 has 2 divisors, whose sum is σ = 131211211202312. Its totient is φ = 131211211202310.
The previous prime is 131211211202221. The next prime is 131211211202377. The reversal of 131211211202311 is 113202112112131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131211211202311 - 227 = 131211076984583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131211211206311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605605601155 + 65605605601156.
It is an arithmetic number, because the mean of its divisors is an integer number (65605605601156).
Almost surely, 2131211211202311 is an apocalyptic number.
131211211202311 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211211202311 is an equidigital number, since it uses as much as digits as its factorization.
131211211202311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 131211211202311 its reverse (113202112112131), we get a palindrome (244413323314442).
The spelling of 131211211202311 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred eleven million, two hundred two thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •